$\left(\frac{2x}{6x+2}\right)-\left(\frac{1}{1}\right)$
$\left(6+4\right)^2+\left(2+-4\right)+6\cdot3$
$xe3-2xe2-x+2$
$\frac{dy}{dx}=1-\frac{y}{10}$
$5\cdot3-4$
$\frac{du}{dx}=\frac{1-x-y}{x+y}$
$12b>-36$
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