$\lim_{x\to\infty}\:\frac{1}{2+1^x}$
$y=\left(x^4-\ln\left(x^3\right)\right)^5$
$\left(2p^5-9\right)\left(2p^5+4\right)$
$\lim_{x\to0}\left(\sqrt{\left(x^2\:+\:6x\:+\:13\right)}\right)-x$
$3x-6x+4$
$x+15y=31$
$7x+25-5x+55$
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