$-2x+6=28$
$\lim_{x\to\infty}\frac{8x-7}{2x+5}$
$2x-5\le5$
$3\left(x+1\right)\left(y\right)^2$
$2x+\left(-2x+3\right)$
$\frac{dy}{dx}+\:px\:=\:3$
$\lim_{x\to\infty}\left(\frac{4-x^2}{1-x}\right)$
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