$x^2-8x-49=0$
$cos^4\left(x\right)-cos^2\left(x\right)=sin^4\left(x\right)-sin^2\left(x\right)$
$\left(h+4\right)\left(h-3\right)$
$\int\left(\frac{\sqrt{4x^2+1}}{x^4}\right)dx$
$3y^{''\:}+2y^{'\:}+8y=0$
$\left(7m\:-4\right)\left(7m\:-1\right)$
$x^2+y^2+3z^2=8$
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