$\left(4^0w^2\right)^{-5}$
$\left(-167\right)-\left(-268\right)$
$xe^1$
$x^2=28$
$2.\left(-3\right):\left(-1\right)$
$9x^4-30x^5y+25xy=x$
$y^{-\frac{1}{3}}\frac{dy}{dx}=1$
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