$\int_{-2}^2\left(\frac{1}{x^2+4}\right)dx$

$\frac{\sin\left(x\right)+\cos\left(x\right)}{\sin\left(x\right)}-1=\frac{1}{\tan\left(x\right)}$

$\sin2c\cdot\sin c=\cos c$

$x^2-3x-54$

$\:100\cdot\:6n^2x^2-150\cdot\:6n^2x^3+200\cdot\:6n^3x^3$

$7x^5+5x^4+x^3$

$3x+2<5x-8$