$dx+\left(x\tan\left(y\right)\right)dy=0$

$\left(8x^2\right)\left(x+3\right)$

$\int\frac{x^2-x+1}{\left(x+4\right)\left(x-2\right)}dx$

$\left\{u-v=5\right\}$

$\lim_{x\to0}\left(\frac{4sin\left(5x\right)-3tan\left(x\right)-x}{2x}\right)$

$\frac{dy}{dx}=\frac{5x\ln\left(x\right)}{t}$

$\int\left(x^2+5\right)^42dx$