Exercise
$\sqrt{\sqrt{3y^3}}\left(\sqrt{^{3y^3}}\right)^{\frac{1}{3}}$
Derivative of this function
$\frac{d}{dy}\left(\sqrt{\sqrt{3y^3}}\sqrt[3]{\sqrt{3y^3}}\right)=9\left(\frac{1}{4}+\frac{1}{6}\right)\left(3y^3\right)^{\left(-\frac{3}{4}+\frac{1}{6}\right)}y^{2}$
See step-by-step solution
Integral of this function
$\int\sqrt{\sqrt{3y^3}}\sqrt[3]{\sqrt{3y^3}}dy=3^{\left(\frac{1}{4}+\frac{1}{6}\right)}\frac{y^{\left(3\cdot \left(\frac{1}{4}+\frac{1}{6}\right)+1\right)}}{3\cdot \left(\frac{1}{4}+\frac{1}{6}\right)+1}+C_0$
See step-by-step solution