$\lim_{x\to\infty}\left(\frac{4x^3+3}{2x^3+3x}\right)^{\frac{x^2+2}{x^2}}$
$\left(2x^{-2}y\right)\left(8x^{-3}y^{-3}\right)$
$\frac{dy}{dx}\left(1-x^2\right)=xy+y$
$2xdx+\frac{x^2}{y}dy=0$
$-2.4x+3.8x-x$
$\frac{dy}{dx}=\frac{4x^3}{3e^y}$
$9x^2-5x+16$
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