$\left(12^2\right)^3\cdot12^{-4}$
$y=y-y^3$
$4x\cos^2\left(x\right)-4\sin\left(x\right)\cos\left(x\right)+4x\sin^2\left(x\right)$
$\left(6x^2-4y\right)\left(6x^2+13x\right)$
$\left(8+3n\right)\left(6\right)$
$\frac{x^2-1}{x}=0$
$9m-4=8m+3$
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