$\left(3x^2-19x+6\right)\left(x+2\right)$

$\frac{\left(x-9\right)}{6}+\frac{3}{2}-\frac{x^2}{3}$

$\frac{5}{6}\left(3x\right)-\frac{1}{2}\left(x-4\right)\ge\frac{1}{3}\left(2x-3\right)-x$

$-3-5-\left(-5\right)-\left(-5\right)$

$\frac{d^2}{dx^2}\left(x^2y^2-6x=6\right)$

$5x-4y+10.-7x-3y-10$

$\left(a\right)\left(a^2b^3\right)$