$\frac{x^{4-a^4}}{x\cdot a}$
$\int\left(4x^2\sqrt{x^3-5}\right)dx$
$\int_1^2\frac{1}{\sqrt{6x-x^2}}dx$
$\lim_{x\to0}\left(x^{\left(\frac{1}{ln\:x}\right)}\right)$
$3+6.4$
$\left(3x^2-4y\right)\left(3x^2+5y\right)$
$-4x^2+18x-47=-6x^2+34x-71$
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