$x+4^2+1$
$xy=4y$
$4x^3-2x^2+x$
$3x+4y+z=-2$
$\csc\left(x\right)\left(\sec\left(x\right)-\cos\left(x\right)\right)$
$\frac{dy}{dx}=3x^2e^{-y},y\left(0\right)=1$
$\int\frac{20x+40}{x^2+6x-8}dx$
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