$\left(x^0y^3\right)^{\frac{1}{6}}$

$\lim_{x\to0}\left(x^2+4\right)$

$\int\frac{\sin\left(\frac{1}{x}\right)}{x^3}dx$

$-3\:a\:b\:c\:\left(2\:a^2\:b^2\:+\:3\:a\:b^2\:c\:-\:c^2\right)$

$4x^2-1+x^3-3x^2+6x-2-6x+x+1$

$\ln\left(x+4\right)-\ln\left(2\right)=4$

$\frac{0.1}{2}$