$\frac{y'}{3}-4y=48x$
$\left(\frac{2^2\cdot3^5\cdot4^2}{16\cdot3^2}\right)^2$
$-7-1+2-1$
$\left(5x-7y^2\right)^3$
$2^3\cdot11$
$\int_0^{3a}\left(x^2\right)dx$
$\log\left(-g+6\right)=10$
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