$\left(10x^3-9xy2\right)$
$\lim_{x\to0}\:\frac{x-tanx}{x-senx}$
$\left(\frac{1}{9}a-a\right)$
$\frac{dy}{dx}=sec\left(6x\right)$
$\left(x^9+5y^3\right)^3$
$\left(1+\tan\left(a\right)\right)\left(1-\tan\left(a\right)\right)$
$4.81\cdot6.1$
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