$\frac{\sin\left(x\right)^3}{\cos\left(x\right)}+\frac{\sin\left(2x\right)}{2}=\tan\left(x\right)$

$\frac{2a-3}{6}=\frac{2a}{3}+\frac{1}{2}$

$\frac{x^4-3x^3+2x^2+5}{x+1}$

$\left(x-8\right)^3$

$18a^3b^2\:-12^5b^3+48a^2b^4$

$\int90dx$

$-2\left(xy^2+\frac{1}{6}x^3y\right)$