$49-14z-z^2$
$27.98+673.11$
$\frac{\sin\left(x\right)+\sin\left(3x\right)}{\cos\left(x\right)-\cos\left(3x\right)}=\cot\left(x\right)$
$12=-\frac{4}{7}u$
$\frac{6x^4-9x-x^2-2}{x^2+1}$
$5\left(-1\right)\left(3\right)$
$-7cos^2x=7sin2x$
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