$3\sqrt{x}+38=41$
$2a^2+28a+98$
$\lim_{x\to0}\left(\frac{2\tan\left(x\right)^2}{x^2}\right)$
$\left(-m+2\right)\left(2m-5\right)$
$0:\left(-520\right):\left(-73\right)$
$\left(\frac{1}{3}a+\frac{1}{4}b\right)^2$
$4x=x+9$
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