$6\left(x^2+1\right)-\left(2x-4\right)\left(3x+2\right)<\:3\left(5x+21\right)$
$x^2+x-1640=0$
$\left(2x+5\right)\left(x-7\right)$
$2b\left(2a-3\right)\left(2a+3\right)$
$\left|27-16\right|$
$\int\sec\frac{1}{2}xdx$
$4\left(3x-7\right)+8x=92$
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