$\left(3a+3\right)^3$
$5m^2+7m+15$
$9x^2+12x+9$
$xy^2dx+3x^3y^2dy=0$
$-31-\left(-47\right)-\left(-19\right)-8-35-\left(-44\right)-17-\left(-33\right)-29-\left(-18\right)$
$\frac{3x^4-4x^3+6x^3-5}{1-2x}$
$x-y'=xy$
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