$7c+2x+2f^2+3x-3c$
$\int\frac{3x^2+6}{\left(x^2-4\right)\left(x-3\right)}dx$
$\left(15-3x\right)^2$
$\left(4x+3\right)\left(2x-9\right)$
$\frac{d}{dx}2x^2+y^5=8$
$0.30\cdot10^6$
$5x-12\le3x-4$
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