$36x^5-6x^2+18x^3$
$\left(+93\right)\cdot\left(+14\right)$
$\lim_{x\to-1}\left(\frac{5x^4+6x^3+8x+9}{x+1}\right)$
$98\cdot98$
$\left(5x^3y\right).\left(3x^2y^5\right)$
$tan^2x=\frac{1}{2}$
$\frac{\left(6b+2ab\right)+\left(6c-2ac\right)}{\left(a+3\right)}$
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