$6x>20$
$-6+12-12+7-3+1$
$\int\frac{x^2+x+1}{x^2\left(x+2\right)\left(x-1\right)}dx$
$\frac{2}{3}x-10=-12$
$\lim_{x\to3}8$
$10-2\left(x-6\right)<4+x$
$\int\frac{\left(4x\right)}{\left(16x^2+1\right)^{\frac{3}{2}}}dx$
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