$m^2+71mn-14m^2-65mn+m^3-m^2-115m^2+56m^3$
$\cos^4\left(3x\right)-\sin^4\left(3x\right)=\cos\left(6x\right)$
$\left(\frac{5}{2}x-3y\right)^2$
$x^2-9x+2$
$\frac{2}{5}y-4+7-\frac{9}{10}y$
$2m^2-7m+12=0$
$2m^2\:-\:4m\:+\:6\:por\:2m\:-\:6$
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