$\left(x-\frac{3}{4}\right)\left(x+\frac{4}{5}\right)$
$15\cdot2y-4\cdot2y-11\cdot2y$
$\frac{dy}{dx}=ln\left(\frac{x}{4+x^2}\right)$
$\left(2x^2+5\right)-\frac{5}{2}$
$\frac{a}{5}=-30$
$x^4+\:5x^3+\:17x^2\:+49x^1\:+12\:$
$xydx-dy=0$
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