$\left(3x+2\right)\:\:\:+\:\:\left(3x+2\right)$
$\frac{2y^4}{y^3-y^2+y-1}$
$ax+bx+x$
$3+-3+4+-4+5+-5+1$
$3x+8\:.\:3x+8$
$\frac{d}{dx}\left(y=e^{\frac{y}{x}}\right)$
$\frac{3}{52}axz\left(13a^2x^3+8x^3z^5+4y^5\right)$
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