$\int\frac{\left(x-3\right)}{\left(x+8\right)}dx$
$5x-7+3xand3x-7+5x$
$5\left(10-1\right)$
$\left(u^2+1\right)^3\:\left(2u+1\right)$
$\left(+25\right)-\left(-18\right)+\left(-1\right)-\left(+3\right)$
$-21-65-13-8-7-15-13-24-22-20-23-7-9-18$
$-10-\left[+5-\left(20-14\right)-7\right]-6+12+\left(-21\right)$
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