$\frac{2}{3}y+4^2$
$\frac{2x+6}{4}+3x\le\frac{x+9}{2}$
$\int\left(5x^2-3x\right)\left(-2x^3\right)dx$
$-3x^2+7x+10$
$5\left(2+4\right)-4$
$\left|5x+\left(2x\right)^2\right|^2$
$\left(4xy^2+8\right)\cdot\left(2xy^2-xy\right)$
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