$5x^2-20x+10$
$4\ln\left(x-5\right)=-8$
$tx'+3x=5t^2$
$\int\:\frac{1}{-\left(x^2+1\right)}dx$
$\left(2r-4-6r^3\right)+\left(5r^3+8-9r^5\right)$
$x^2+10x+22$
$\int\frac{5x^2+3x-1}{\left(x^2-x-2\right)\left(x-2\right)}dx$
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