$\tan^2\left(x\right)-1=0$
$\left(2\right)\left(-20\right)\left(5\right)$
$\lim_{x\to\infty}\left(\frac{9x^2+x-6}{3x^2-6}\right)$
$x^2+7x=-15$
$\int\frac{\left(5x\right)}{\left(4-x^2\right)^3}dx$
$18\sqrt{4}+47\sqrt{4}$
$4x^2-x^2$
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