$\left(x^2+3x+2\right)\left(x+3\right)$
$\frac{-9tan\left(x\right)}{9sec\left(x\right)}$
$-8\left(2a+6\right)-6\left(a-6\right)$
$2x^2\:-5x+2=0$
$\frac{x-7}{4}\le8$
$14\left(3+1\right)-12\left(-1-2\right)-42\left(9-9\right)$
$\left(-5\right)-\left(-5\right)-6$
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