$\int\:\frac{x^2+6x+4}{x^4+8x^2+16}dx$
$2\cdot2\cdot2$
$\frac{1+tan^2x}{sec^2x}$
$\left(\left(t\cdot\left(1-t^2\right)^{-0.5}\right)^2+1\right)^{0.5}$
$5 x + 4 > 79$
$\left(ab-2b\right)\left(ab+2b\right)$
$z^2-8z+5$
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