$-7a-7-1$
$x^2-2x=8$
$10b-4+6-5b+2a-\left(-2a+3b-5+2a\right)-3b-7$
$\frac{\left(-x^6+5x^4+3x^3-2x+8\right)}{\left(4+x\right)}$
$x^6-1=0$
$\left(m+2\right)\left(n+6\right)$
$1\le\frac{1}{3}-2x$
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