$x^2-8x=7$
$\frac{-7}{\infty}$
$\left(-9\right)\left(-4\right)\left(8\right)$
$\int\frac{1}{x\frac{2}{3}}dx$
$\frac{\sqrt{\sec\left(x\right)-1}}{\left(\sec\left(x\right)+1\right)}$
$\frac{5x^2-17x-12}{x-4}$
$\frac{2x^4+5x+4}{x}$
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