$6g+5-9g+2$
$\frac{\left(sec\:a\:-\:tana\right)}{seca\:+\:tan\:a}$
$\frac{-1+\sqrt{9}}{2}$
$\int_0^2\left(\sqrt{a^2+b^2}\right)dt$
$\frac{dy}{dx}=\frac{x^2-y}{4}$
$8-0.33$
$c^8-9$
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