$\left(5+9i\right)-\left(-4-2i\right)$

$\left(a\right)+\:\left(\frac{1}{2}\right)^2$

$7\left(q+9\right)$

$\left(-9\right)-\left[-6-\left(3+2-1\right)+3\right]$

$5x-1>3x+7$

$\lim_{x\to\infty}\left(\frac{3\cdot x^2+4\cdot x^3+3^{x+2}}{x\cdot2^x+2\cdot3^x}\right)$

$4x^4-4x$