$+5+-3\:x\:+8\:+\left(-\frac{28}{+7}\right)+3\:\left(+\frac{36}{-9}\right)$
$y'\:-\:4y\:=\:10$
$\frac{x^4}{2+x^2}$
$\left(-2v^2x\right)^5\left(3v^{-1}x^3\right)^2$
$\left(1\:-\:4m\right)^3\:$
$-x^2-4x<-5$
$\frac{x^3}{\left(x^4+3\right)^2}$
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