$\int\frac{x^2+x}{\left(x^2+1\right)\left(x-3\right)}dx$
$r^{16}-z^2$
$1x^2+bx+c$
$\lim_{x\to0}\left(\frac{e}{x^2}\right)$
$10^4\cdot10^{-6}$
$\int\left(x^{\left(\frac{3}{2}\right)}+8\right)^4dx$
$\sqrt{10x^3+x^4+25+50x+35^2}$
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