$\lim_{x\to-8}\left(\frac{2x^2+5x-24}{x+8}\right)$
$-2\left(6+5g\right)$
$\frac{dy}{dt}=\frac{y^2}{t}$
$\int_0^4\left(\frac{\left(x+1\right)^2}{\sqrt{x}}\right)dx$
$12\:-\:x\:\le9$
$3x^2-9x-1$
$\int\frac{\left(x^2\right)}{\sqrt{64-x^2}}dx$
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