$-8-\left(-56\right)$
$6=m+6$
$\int\left(\frac{1}{\sqrt{\left(36-x^2\right)}}\right)dx$
$\left(4x\:+8y+3\right)^2$
$\lim_{x\to\infty}\left(\frac{\sqrt{1-x^2}}{36x^2-1}\right)$
$\frac{x^3\cdot\:\:x^{-4}}{x^{-3}\cdot\left(-x\right)^6}$
$0.5x-4x+1.5x$
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