$\lim_{x\to\infty}\left(\frac{3x^2+7x}{3x^3+2x+3}\right)$
$3a-6^2+2b^2x-6ax$
$\left(23a+41b\right)\left(23a-41b\right)$
$4x^4+20^6+15^6$
$25^2^a\:-|2|^2^b$
$dx-e^3x\:dy=0$
$\left|\frac{\left(2+i\sqrt{5}\right)\left(1+i\sqrt{3}\right)^3}{\sqrt{5}+i\sqrt{3}}\right|$
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