$0^2\:are\:sec\:$
$\left(\frac{\sqrt{2}\cdot x^{-2}}{\sqrt{16}\cdot x^3}\right)^{-2}$
$-8g-2-9g+2$
$x+10<10$
$\left(24^2\right)^4$
$\int\left(\frac{1}{\left(\sqrt{2+4x}\right)}\right)dx$
$5x-9>12$
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