$\left(25u^2v-6wx^5\right)^2$
$\frac{x+2}{x+4}=\frac{x-2}{x+2}$
$\frac{\left(-2xy^2\right)\left(5x^{2y}\right)}{\left(5y^2\right)\left(-4x^5\right)}$
$v^2+14v+49$
$\sqrt[5]{128t^{17}w^{15}}$
$\:x\left(x\:+\:4\right)\:+\:6\left(x\:+\:4\right)$
$\lim_{y\to2}\sqrt{y^2+2y+1}$
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