$\int-2x^3\cdot e^{-\frac{7}{8}}x$
$2\left(1\right)^2+4\left(1\right)$
$\lim_{x\to\infty}\left(\frac{2}{3\left(x+2\right)}\right)$
$-125\cdot8$
$\sqrt{8}0\:x^2y^8\:\:$
$0.3+4\sqrt{5}$
$\int\frac{y^4-8}{\left(y^3+2y^2\right)}dy$
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