$2^{-4}\cdot2^2$
$24\:x^8\:y^3-16\:x^6\:y^7\:z$
$\frac{x^2-2x}{x^3-3x^2+2}$
$\left(16x+8y-240\right)^2$
$\frac{dy}{dx}=\left(2y-x\right)\left(x^{-1}\right)$
$\frac{d}{dx}x^2\sqrt{xy}-y^2=52$
$\left(x^2-3x^2+3x-3\right)\left(2x+2\right)+\left(-8\right)$
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