$2\:3\:1\:7=x$
$\left(\frac{1}{2}p^5-3r^4+4s^3\right)^2$
$\left(\left(x+4y\right)^{\frac{1}{5}}\right)^3$
$x\left(3+x\right)$
$\left(5c+8\right)\left(3c-1\right)$
$x^2+2xy-7xy+4y^2$
$3.75\cdot12$
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