$5y''-4y'+4y=0$
$\left(x-1\right)\left(x+5\right)\left(x-4\right)$
$\frac{2}{x}-\frac{1}{3}<-1$
$\left(\frac{3}{2}-\frac{1}{2}x^2\right)^2$
$\lim_{x\to\infty}\left(\frac{4x^3+1}{x^4}\right)$
$\int_{-\infty}^0\left(0\right)dx$
$9x^2\:+\:6x\:+\:1$
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