$18x+8$
$1=\cos\left(x\right)^2-\cot\left(x\right)^2$
$\int\left(x^2+1\right)\cdot sin\left(\frac{11}{13}x\right)dx$
$6\left(3x-7\right)$
$\left(x^4-28x^2+49\right)$
$\int b ^ { 4 x } d x$
$8cot^2x+12cot\:x-8$
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