$4x^4-36$
$-10=91-x$
$\left(x^4\right)^{-3}\cdot2x^4$
$40x^2-41x-42=0$
$\frac{du}{df}=\frac{4+f^4}{uf^2+f^2u^4}$
$\sin\left(3x\right)dy=4\cos\left(2y\right)dx$
$25\:+\:-78\:+\:-32\:\cdot\:-12$
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